A no. is increased by 20 % and decreased again by 20 % and thus a new no. is formed.
By what % should this no. be changed to get the original no.???????
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Let the number to = 100
Increase in the number= 20% of 100
= (20/100)×100= 20
Increased Number = 100 + 20= 120
The resulting number decreased by 20%
Decrease in the number= (20/100)×120))= 12×2=24
New number= 120-24 = 96
Now, net decrease =100-96 = 4
Net %Decrease = (net decrease/ Original number × 100) %
=( ( 4/ 100 )×100) %
= 4%.
Hence, net percent decrease= 4%
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