Question

a no.of 2- digits has 3 for its ones digit and the sum of the digits is 1/7 of the no.what is the no​

Answer 1

Answer:

63

Step-by-step explanation:

let the tens digit is x and the given ones digit is 3

then the number will be 10x+3

given sum of the digits=1/7 of the number

that is ,     x+3 = 1/7 * 10x+3

               x+3=10x+3/7

             7x+21=10x+3

                  21-3=10x-7x

                    18=3x

                      x=18/3

                      x=6

so the number will be 10x+3=10*6+3=60+3=63

required number is 63.

Answer 2

Answer:

63

Step-by-step explanation:

Let tens digit be X

So 10X+3(1/7)=X+3...

After solving this you will get the answer