Question

A no. when added to it's half gives 39 what is the no.

Answer 1

$\text{ Hey there !} \\ \\ \text{ Solution: } \\ \\ \text{ Let the number be denoted as x.} \\ \\ When \: written \: in\: equation \: form \: we \: get \\ \\ \implies x + \dfrac{x}{2} = 39 \\ \\ Taking \: LCM \: we \: get, \\ \\ \implies \dfrac{ 2x + x }{2} = 39 \\ \\ \implies \dfrac{3x}{2} = 39 \\ \\ \implies 3x = 39 \times 2 \\ \\ \implies 3x = 78 \\ \\ \implies x = \dfrac{78}{3} = 26 \\ \\ \boxed{ Hence \: the \: unknown \: number \: is \; 26} \\ \\ \text{ Hope my answer helped !}$

Answer 2

heya...

Here is your answer...

Let us take the number as x.

When it is added to it's half gives 39.

i.e.

x+x/2 = 39

2x+x/2 = 39

3x/2 = 39

3x = 39×2

3x = 78

x = 78/3

x = 26

Therefore the number is 26.

Proof: x+x/2 = 39

=) 26+26/2 = 39

=) 26+13 = 39

=) 39 = 39

It may help you...☺☺