Math, asked by gg1668070, 2 months ago

A no. when divided by 36,24and 16,leaves the remainder 11 in each case. find the smallest value of this no.​

Answers

Answered by Barani22
1

Answer:

.

Step-by-step explanation:

Least number when divided by 12,16,24,36 and leaves remainder 0

=LCM of 12,16,24,36

So,LCM leaves remainder 0

So,Required number will be 7 more than LCM

∴ Required number=LCM+7

Factors of 12=2×3×2

Factors of 16=2×2×2×2

Factors of 24=2×2×2×3

Factors of 36=2×2×3×3

∴ LCM=2×2×2×2×3×3=16×9=144

So,Required

Answered by Anonymous
5

Answer:

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