Question

a no. when divided by a divisor leaves a remainder of 24 when twice the original no. is divided by the same divisor the remainder is 11.then divisor is -​

Answer 1

Answer:

= 37

Step-by-step explanation:

quotient = q  

divisor = d  

dividend = N

Given:-

N = D(Q1) + 24

2N = D(Q2) + 11

We multiply the first equation by 2 and get  

2N = 2D(Q1) + 48  

2N = D(Q2) + 11

Subtracting, we get

0 = D(2Q1 - Q2) + 37

Which implies D(2Q1 - Q2) = 37.

Hence, the divisor is 37.

Since 37 is prime, D is either 1 or 37. If D were 1, the remainder would always be zero, so it must be 37.

Explanation:-

A number when divided by a divisor leaves a remainder of 24 when twice of the original number is divided by the same divisor the remainder is 11 what is the value of the division.

Answer 2

Answer:

Let the number is N, the divisor = D,

I will make the two equations-

N = xD+24

2N = yD+11

where x and y are integers

Solving them: D(y-2x) = 37

as D is also integer and 37 is a prime number, the D should be 37 to satisfy the above equation.

Hence answer is 'D'