Question

A no. when divides 41 and 68 leaves 5 as the remainder . What is the no.?

please help me with this maths word problem​

Answer 1

Step-by-step explanation:

The number which divides 41 and 68 leaving a remainder of 5 should be the HCF of (68-5) and (41-5),i.e.,63 and 36

Now,

63>36

So,a=63 and b=36

Applying Euclid's Division Lemma,

a=bq+r

=>63=36×1+27

As,r≠0

=>36=27×1+9

As,r≠0

=>27=9×3+0

Thus,9 is the HCF of (63,36)

Verification:

41÷9=5

and. 68÷9=5

Hence,9 is the required number

Answer 2

Answer:

Hey dude your answer is 9.

Step-by-step explanation:

41- 5=36

68-5=63

Now, we have to find the HCF of these numbers.

The HCF of 63 and 36 is 9.

If answer is right then Please mark it as brainliest.