Question

a non conducting ring of radius R has two positive point charges lying diametrically opposite to each other each of magnitude Q .the ring rotates with an angular velocity omega. if is the equivalent current then.

Answer 1

Answer:

The equivalent current is Qω/2π

Explanation:

The non conducting ring has the radius R,

and the magnitude of the total charge is =Q

According to the ring rotates with an angular velocity ω

Now the average magnitude of the charge = the whole charge passing through a point in unit time

charge passes in one rotation of ring= Q

Therefore the time taken in one rotation= 2 π R/ωR

                                                     = 2 π /ω

Therefore the equivalent current is dQ/dt

                                       = Qω/2π