Question

A non-conducting solid sphere of radius 2.0 carrying thin spherical shell of radius 4.0 m carrying net negative charge 25nc. Determine the electric fields at the distance of 1.0 m, 3.0 m and 10. 0 m, respectively, from the center of the sphere​

Answer 1

Answer:

Step-by-step explanation:

Now we have given the radius as 0.5 m, So according to Gauss law:

∫E dA = 1 / ∈o ∑q(i)

E x 4πr² = 1 / ∈o x { q /( 4/3 x π x R1³) } x 4/3 x π x r³

E = q1 x r / 4π∈oR1³ = 18 x 10^9 x 0.5 / 4 x 3.14 x 8.85 x 10^-12 x 1³

After calculations, it comes out to be: 162 V/m

Now r = 1.5, we have:

∫E dA = 1 / ∈o ∑q(i)

E x 4πr² = 1 / ∈o x q1

E = q1 / 4π∈o x r² = 18 x 10^9 / 4 x 3.14 x 8.85 x 10^-12 x (1.5)²

After calculations, it comes out to be: 72 V/m

Now r = 2.5, we have:

∫E dA = 1 / ∈o ∑q(i)

E x 4πr² = 1 / ∈o x (q1 - q2)

E = q1 - q2 / 4π∈o x r² = (18 - 20) x 10^9 / 4 x 3.14 x 8.85 x 10^-12 x (2.5)²

After calculations, it comes out to be: -1.31 V/m

Answer:

So the electric fields at the distances of 0.5 m, 1.5 m, and 2.5 m, respectively are 162 V/m , 72 V/m and -1.31 V/m from the centre of the sphere.