Question

A non-ideal gas is heated slowly and expands reversibly at a constant pressure of 275 torr from a volume of 385 cm3 to 875 cm3. Work done by the system is (in Joules)

Answer 1

Answer:

Work done by the system is  -18.0 J.

Explanation:

Step 1: Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. For a constant force acting in the same direction as the motion, the work is simply equal to the product of the force's magnitude and the distance travelled.

$W = -P_{ext}(V_f-V_i)$

$P= 275.0 torr$

= $\frac{ (275.0)}{760}$ atm

= 0.3618 atm

$V_i= 385 cm^3$

= (385$\times$0.001) L

= 0.385 L

$V_f= 875 cm^3$

= (875$\times$0.001) L

= 0.875 L

Step 2:Work = Force Distance is the formula for calculating work. The joule (J), sometimes known as the Newton metre (N m), is the SI unit for labour. When an item is moved across a distance of 1 m by 1 N of force, the work done is equal to 1 joule.

put values in above expression

$W = -P_{ext}(V_f-V_i)$

W = -0.3618 (0.875L - 0.385L)

W = -0.1773 atm.L

W = -0.1773$\times$101.33 J

W = -18.0 J

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