Question

A non reacting gaseous mixture contains Sulphur dioxide and sulphur trioxide in the mass ratio 1 : 5 .find the ratio of the numbers of the molecules

Answer 1

here it is given the mass ratio of Sulphur dioxide and sulphur trioxide is1 :5 .

let take mass of Sulphur dioxide =x
and molecular mass is =
so,
one mole of any substance contains the number of molecules equal to Avogadro number.
i.e
1 mole of SO2 contains = 6.022×10^23
and
5 mole of SO3 contains = 5 × 6.022× 10^23

hence the Ratio is.

=6.022×10^23/6.022×10^23×5
=1/5
so ratio is

1:5

Answer 2

Hii frnd...

A to Q

$\frac{SO2}{SO3} = \frac{1}{5}$ (BY MASS)

If we take 1 gram of SO2 then mass of SO3 would be 5 grams
So calculate number of moles for both...

Mole of SO2= Given mass/GMM
=1/64

Number of molecules of SO2 will be $\frac{1}{64} *6* 10^{23}$
=$9.3* 10^{21}$ molecules of SO2.

Mole of SO3=Given mass/GMM
=5/80

Number of molecules of SO3 will be $\frac{5}{80}*6* 10^{23}$
=37.5*$10^{21}$

Ratio=$\frac{9.3* 10^{21} }{37.5* 10^{21} }$
=9.3/37.5
=3.1/12.5

Hope it helped u!!!