Question

a non stochiometric compound of Fe has a formula Fe0.93O. Percentage fraction of Fe present as Fe2+ and Fe3+ ions are


•80% 20%
•90% 10%
•15% 85%
•85% 15%​

Answer 1

Answer:

In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.

However, here number of Fe2+ present = 0.93

Or No. of Fe2+ ions missing = 0.07

Since each Fe2+ ion has 2 positive charge, the total number of charge due to missing (0.07) Fe2+ ions = 0.07 * 2 = 0.14

To maintain electrical neutrality, 0.14 positive charge is compensated by the presence of Fe3+ ions. Now since, replacement of one Fe2+ ion by one Fe3+ ion increases one positive charge, 0.14 positive charge must be compensated by the presence of 0.14 Fe3+ ions.

In short, 0.93 Fe2+ ions have 0.14 Fe3+ ions

100 Fe2+ ions have = 0.14/0.93 * 100 = 15.05%

Explanation:

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Answer 2

Answer:

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