Question

A non uniform rod of mass 100 g is balanced as shown. Where should the 80g mass be placed if the rod is now balanced 50 cm from end A

Answer 1

Answer:

As 100g is balanced at fulcrum it will have a perpendicular distance of 40cm from itself and mass m will have 40−20=20cm distance.

Explanation:

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Answer 2

Answer:

As 100g is balanced at fulcrum it will have a perpendicular distance of 40cm from itself and mass m will have 40−20=20cm distance.