Question

a) none
(d) none
80.) Between first & second quartile, the frequency is equal to
(a) 3N/4
(b) N /2
(C) N /4
81.) Between second & upper quartile, the frequency is equal to
(WBN/4
(b) N /4
(c) N /2
(d) none​

Answer 1

Answer:

a none is the right answer................

Answer 2

Answer:

80. c

81. b

Step-by-step explanation:

80. becauses there are four quartiles and each quartile is divided into equal parts as in N/4 area.

first quartile frequescy =N/4

Second quartile frequesncy =2N/4

So, the frequescy between first and second is 2N/4 -N/4

=N/4

81. upper quartile is the median of first half of data set,

So the frequency of upper quartile is given by 3N/4

and difference is 3N/4 - 2N/4

=N/4