Question

a normal die is rolled.calculate the probability that the number on the uppermost face when it stops rolling will be (a) an even prime number​

Answer 1

Answer:

1/6

Step-by-step explanation:

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A ={2}

n(S) =6

n(A) =1

P(A) =n(A)/n(S)

= 1/6

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Answer 2

Answer:

sample space=(1,2,3,4,5,6)

n(s)=6

event A=no. on upper face is prime no.

=(2,3,5)

n(A)=3

p(A)=n(A)/n(s)

=3/6

=1/2