Question

A normal vision female whose father is color-blind marries a normal vision male. What would be the probability of her sons and doughters to be colour blind

Answer 1

Answer: The probability of son having colorblindness is 1/2 whereas that of daughter having colorblindness is zero.

Explanation-

Colorblindness is a X- linked recessive disorder. A normal vision female whose father is colorblind would be carrier for the disease as she will receive affected X chromosome from her father.

The genotype of parents will be- $X^{c} X$ and $XY$ ( normal vision male). They can produce normal male ( XY), colorblind male ( $X^{c}Y$) , normal female ( XX), and carrier female ( $X^{c} X$).

Refer the cross.