Question

A not-so-good clockmaker has four clocks on display in the window. Clock #1 loses 15 minutes every hour. Clock #2 gains 15 minutes every hour relative to clock #1 (i.E., as clock #1 moves from 12:00 to 1:00, clock #2 moves from 12:00 to 1:15). Clock #3 loses 20 minutes every hour relative to clock #2. Finally, clock #4 gains 20 minutes every hour relative to clock #3. If the clockmaker resets all four clocks to the correct time at 12 noon, what time will clock #4 display after 6 actual hours (when it is actually 6:00 pm that same day)? 5:00 5:34 5:42 6:00 6:24

Answer 1

Answer:

Place the motion to make the best of the form assembly and then