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A
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Rahim purchased a used car and sold it on 5% profit to Sarvesh, Sarvesh spent Rs. 6500 on repairing it and
then he sold it on 10% profit to Mohan. Mohan sold it to Rita on 6% loss. Rita spent Rs. 1280 in reparng and
sold it to her relatives without any profit or loss in Rs.84000. What is the cost price in rupees) of the Car
when Rahim bought it?
65.000
(57313
167313
167313
167313
68.000
70.000
1673757160
1573737107
o 6000​

Answer 1

Solution :-

Let us assume that, Rahim bought the car at Rs.100x .

so,

→ CP for rahim = Rs.100x

→ Profit = 5%

→ SP for rahim = CP for Sarvesh = (100x * 105)/100 = Rs.105x .

now,

→ CP for Sarvesh = Rs.105x

→ Spent on reparing = Rs.6500.

so,

→ Total CP = Rs.(105x + 6500)

→ Profit = 10%

→ SP for Sarvesh = CP for Mohan = (110/100)(105x+6500) = Rs.{1.1(105x + 6500)}

now,

→ CP for Mohan = Rs.{1.1(105x + 6500)}

→ Loss = 6% .

→ SP for Mohan = CP for Rita = (94/100){1.1(105x + 6500)} = (0.94 * 1.1)(105x + 6500) = Rs.{1.034(105x + 6500)}

now,

→ CP for rita = Rs. {1.034(105x + 6500)}

→ Spent on reparing = Rs.1280

→ Total CP for rita = {1.034(105x + 6500)} + 1280

→ SP for rita = Rs.84000

A/q,

→ Total CP for rita = SP for rita

→ {1.034(105x + 6500)} + 1280 = 84000

→ {1.034(105x + 6500)} = 84000 - 1280

→ {1.034(105x + 6500)} = 82720

→ 105x + 6500 = 80000

→ 105x = 80000 - 6500

→ 105x = 73500

→ x = 700

therefore,

→ Rahim bought the car = 100x = 100 * 700 = Rs.70000 (Ans.)

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