Question

A nozzle is a device for increasing velocity of a
steadily flowing stream. At the inlet of a certain nozzle,
the enthalpy and velocity of fluid are 3000 kJ/Kg and
60 m/s respectively, whereas the enthalpy is 2500
kJ/Kg at the discharge end. The nozzle is horizontal
and there is negligible heat loss from it. Find the exit
velocity of the nozzle.
(1) 900.5 m/s (2) 708.4 m/s
(3) 775.0 m/s (4) 1000 m/s

Answer 1

Answer:

Explanation:

=> Steady flow energy equation can be used to calculate the exit velocity C_2.  

=>but here, it is given that  The nozzle is horizontal and there is negligible heat loss from it.

=> Thus, we can write the equation as following:

$h_1 + C_1^{2} / 2 = h_2 + C_2^{2} / 2$

$3000 * 10^3 + 60^{2} / 2 = 2500 * 10^3 + C_2^{2}$

$C_2$ = 1001.79 m/s ≃ 1000 m/s

Thus,  the exit velocity of the nozzle is approx 1000 m/s.