Question

A nucleus of an atom of 92Y235, initially at rest, decays by emitting an -particle as per the equation 92Y235 →90X231 + 2He4 + energy It is given that the binding energies per nucleon of the parent & daughter nuclei are 7.8 MeV & 7.835 MeV respectively and that of -particle is 7.07 MeV/nucleon. Assuming the daughter nucleus to be formed in the unexcited state & neglecting its share in the energy of the reaction. Calculate the speed of the emitted - particle. (Take the mass of -particle to be 6.68 X 10-27 Kg).

Answer 1

speed emitted is 10×10^18 m/s

Answer 2

Answer:

HEY DUDE!!

10*10^18 m/s is ur answer..

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