Question

A nucleus with mass number 220 initially at rest emits anparticle. If the Q
value of the reaction is
5.5MeV, calculate the kinetic energy of particle.​

Answer 1

Explanation:

M→X+α

E=

2m

p

2

Let Total energy = T

T=E

α

+E

X

M=M

α

+M

X

M

X

=216

Conservation of momentum

p

α

=p

X

m

α

E

alpha

=m

X

E

X

E

α

=

M

m

x

T

E

α

=

220

216

5.5=5.4MeV