Question

A number 10x + y is multiplied by another number 10a+b and the result comes as 100p + 10q + r, where r = 2y, q = 2(x + Y) and p = 2x ; x, y

Answer 1

According to problem
(10x+y)(10a+b)=100p + 10q + r
By substituting the values
r=2y
q=(2x+y)
p=2x
(10x+y)(10a+b)=100*2x+10*2(x+y)+2y
(10x+y)(10a+b)=220x+22y
10a+b=22

Answer 2

Answer:

The required number is 22.

Step-by-step explanation:

To find : A number $10x+y$ is multiplied by another number $10a+b$ and the result comes as $100p + 10q + r$, where $r = 2y$, $q = 2(x + y)$ and $p = 2x$; x, y ?

Solution :

According to question,

$(10x+y)(10a+b)=100p + 10q + r$

Substitute the values,

$r = 2y$, $q = 2(x + y)$ and $p = 2x$

$(10x+y)(10a+b)=100(2x) + 10(2(x+y))+2y$

$(10x+y)(10a+b)=200x+20x+20y+2y$

$(10x+y)(10a+b)=220x+22y$

$(10x+y)(10a+b)=22(10x+y)$

On comparing,

$10a+b=22$

Therefore, the required number is 22.