A number 10x+y is multiplied by another number 10a+b and the result comes as 100p+10q+r, where r =2y, q = 2(x+y) and p =2x ; x, y<5, q ≠ 0. Find the value of 10a+b.
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Answered by
32
Acc. to ques,
(10x + y)(10a + b) = 100p + 10q + r ...........................(1)
it is given that r=2y,q=2(x+y)=2x+2y & p=2x
put in (1)
⇒ (10x + y)(10a + b) = 100(2x) + 10(2x+2y) + 2y
⇒(10x + y)(10a + b) = 200x + 20x + 20y + 2y
⇒(10x + y)(10a + b) = 220x + 22y
⇒(10x + y)(10a + b) = 22(10x + y)
Divide both sides by (10x + y)
⇒ 1 ×(10a + b) = 22(1)
⇒10a + b = 22 Ans
(10x + y)(10a + b) = 100p + 10q + r ...........................(1)
it is given that r=2y,q=2(x+y)=2x+2y & p=2x
put in (1)
⇒ (10x + y)(10a + b) = 100(2x) + 10(2x+2y) + 2y
⇒(10x + y)(10a + b) = 200x + 20x + 20y + 2y
⇒(10x + y)(10a + b) = 220x + 22y
⇒(10x + y)(10a + b) = 22(10x + y)
Divide both sides by (10x + y)
⇒ 1 ×(10a + b) = 22(1)
⇒10a + b = 22 Ans
Answered by
11
Answer:
HII, MATE IN THE ABOVE IMAGE IS THE ANSWER ,STEP-BY-STEP.
ANSWER =22
DON'T FORGET TO CLICK ON A SMALL HEART
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