Math, asked by e6lvangelmurtaitra, 1 year ago

A number 10x+y is multiplied by another number 10a+b and the result comes as 100p+10q+r, where r =2y, q = 2(x+y) and p =2x ; x, y<5, q ≠ 0. Find the value of 10a+b.

Answers

Answered by kaurjyoti
32
Acc. to ques,
    (10x + y)(10a + b) = 100p + 10q + r ...........................(1)
it is given that   r=2y,q=2(x+y)=2x+2y & p=2x
               put in (1)
 ⇒ (10x + y)(10a + b) = 100(2x) + 10(2x+2y) + 2y
⇒(10x + y)(10a + b) = 200x + 20x + 20y + 2y
⇒(10x + y)(10a + b) = 220x + 22y
⇒(10x + y)(10a + b) = 22(10x + y)
 Divide both sides by (10x + y)
⇒ 1 ×(10a + b) = 22(1)
10a + b = 22     Ans


Answered by mohitgurjar59
11

Answer:

HII, MATE IN THE ABOVE IMAGE IS THE ANSWER ,STEP-BY-STEP.

ANSWER =22

DON'T FORGET TO CLICK ON A SMALL HEART

Thank you

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