A number 15 is divided into 3 parts which are in arithmetic progression and the sum of their square is 83. Find the smallest number? How to find? Plzz help
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let a-d,a,a+d are the three parts of AP
→a-d+a+a+d=15
→3a=15
sum of their squares is 83
→(a-d)²+a²+(a+d)²=83
→a²+d²+a²+a²+d²=83
→3a²+2d²=83
→3(25)+2d²=83
→75+2d²=83
→2d²=8
d²=4
d=±2
the numbers are 3,5,7
the least number is 3
→a-d+a+a+d=15
→3a=15
sum of their squares is 83
→(a-d)²+a²+(a+d)²=83
→a²+d²+a²+a²+d²=83
→3a²+2d²=83
→3(25)+2d²=83
→75+2d²=83
→2d²=8
d²=4
d=±2
the numbers are 3,5,7
the least number is 3
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