Math, asked by subhashvarma710, 2 months ago

A number 32 a6a is divisible by 3 find what values can hold ?also find all such numbers.

Answers

Answered by Anonymous

15

Answer:

» 32a6a is divisible by 3

Therefore, by divisibility of 3

» 3 + 2 + a + 6 + a is divisible by 3

Hence, 11 + 2a is divisible by 3

» a = 2

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