Question

A number 32a6a is divisible by 3. Find what values can a hold? Find all such numbers.​

Answer 1

Step-by-step explanation:

So , a number is divisible by 3 if sum of digits is divisible by 3

Adding the digits of the number

3+2+a+6+a = 11+2a

So the number is of the form 11+2a

Now we get a = 3 , 6 and 9

since a cannot be 2 digit number hence we get

a=3 ,6 and 9 Answer

Answer 2

Answer:

sum of the digits in 32a6a = 3+2+a+6+a = 11+2a

since, the number 32a6a is divisible by 3, the sum of digits is definitely divisible by 3.

which implies that

11 + 2a = 15, 21, 27,...

or a = 2, 5, 8 ,...

therefore, the numbers are : 32262 , 32565 , 32868.