Question

A number 344ab5 is divisible by both 9 and 25 find the number

Answer 1

It is divisible ithink so the no is3

Answer 2

The required number is 344025.

Explanation:

We have,

344ab5

To find, the required number = ?

We know that,

The number is divisuble by 5, the unit digit of the number = 0 or 5

and

The number is divisuble by 9, the sum of the digits is divisible by 9.

∴ 344ab5 (already unit digit is 5)

3 + 4 + 4 + a + b + 5 = 16 + a + b

Put a = 0 and b = 2

⇒ 16 + 0 + 2 = 18, is divisibe by 9.

∴ The required number = 344025

Hence, the required number is 344025.