Question

A number 34A is exactly divisible by 2 and leave remainder when is divisible by 5 find A​

Answer 1

Answer:

The number 346 is exactly divisible by 2 and leaves a remainder 1 when divided by 5.

Given, the number is 34A and also it is given that 34A is divisible by 2.

Step-by-step explanation:

Then A is an even number since its divisible by 2.

It can be 2,4,6,8......

Now that we have the options let's find numbers that gives remainder 1 when divided by 5.

From the above number,

Only 6 gives remainder 1 when divided with 5.

So 6 is the number.

Extra (if needed)

If the remainder is 2 then the number will be 3.

Likewise if the remainder changes we can find the number too.

Here the remainder is 1,

So A= 6

Therefore,

The number is 346

Hope it's what you are looking for.

Sorry if made any mistakes.