Question

a number 34A is exactly divisible by 2 and leaves a remainder 1, when divided by 5 find A

Answer 1

Answer:

The number 346 is exactly divisible by 2 and leaves a remainder 1 when divided by 5.

Step-by-step explanation:

Given, the number is 34A and also it is given that 34A is divisible by 2.

Hence, A can be 2, 4, 6, 8.

Next it is given that 34A when divided by 5 it leaves a remainder of 1.

Hence if A = 6, Then, 6÷5 leaves a remainder of 1.

So, A = 6 and the number must be 346 only.

Answer 2

In question it is given that the number 34A is exactly divisible by 2. it is possible when unit digit is 0,2,4,6,8.

next it is given that it leaves a remainder 1,when it is divides by 5

Step-by-step explanation:

if A= 2

342

it is divisible by 2

342÷5= 68.5

so it is not A

if A =4

344

it is divisible by 2

344÷5=68.8

so it is not A

if A=6

346

it is divisible by 2

346÷5=1

so it is A

therefore A=6