a number 3A is exactly divisible by 2 and leaves a remainder 1 when divided by 5 find A
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Assume A = 2 ,
Condition - 1
3×2=6 (and 6 is exactly divisible by 2) 6÷2=3
Condition - 2
When 6 is divided by 5 , it leaves a remainder 1 .
This assumption fulfills both the conditions .
Hence , A= 2 .
Condition - 1
3×2=6 (and 6 is exactly divisible by 2) 6÷2=3
Condition - 2
When 6 is divided by 5 , it leaves a remainder 1 .
This assumption fulfills both the conditions .
Hence , A= 2 .
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