Question

A number, 3N when divided by D, leaves a remainder of 13, where N and D are natural numbers. If 4N is divided by D, the remainder is 9. What will be the remainder when N is divided by D?​

Answer 1

$\\\\\huge{⚝}$ $\\\\\huge{\underline{\mathcal{Answer}}}$

$\\\huge{☞}$$\\\sf \dfrac{n}{d}$ = -4

$\\\\\huge{⚝}$ $\\\\\huge{\underline{\mathcal{Given}}}$

$\\\huge{↬}$$\\\sf \dfrac{3n}{d}$ = 13 .... (1)

$\\\huge{↬}$$\\\sf \dfrac{4n}{d}$ = 9 .... (2)

$\\\\\huge{⚝}$$\\\\\huge{\underline{\mathcal{To Find:}}}$

$\\\huge{→}$$\\\\\sf \dfrac{n}{d}$

$\\\\\huge{⚝}$ $\\\\\huge{\underline{\mathcal{Steps:}}}$

$\large{⇒}$Subtracting (1) from (2),

$\large{⇒}$$\sf \dfrac{4n}{d} - \dfrac{3n}{d} = 9 - 13$

$\large{⇒}$$\sf \dfrac{4n-3n}{d}=-4$

$\large{⇒}$$\sf\dfrac{n}{d} = -4$

$\\\\\fbox{\fbox{\fbox{\fbox{\huge{\underline{\underline{\sf{\green{Hope \: it \: helps}}}}}}}}}$