A number 40xyy129 is divisible by 33. Find the possible value x
y .also find the number
Answers
x = 4 and y = 2 , 5 , 8 , Numbers 40422129 , 40455129 & 40488129
Step-by-step explanation:
A number 40xyy129 is divisible by 33.
Divisible by 33
33 = 3 * 11
=> Divisible by 3 & 11
Divisible by 3 if sum of digit is divisible by 3
=> 4+ 0 + x + y + y + 1 + 2 + 9 is divisible by 3
=> x + 2y + 16 Divisible by 3
Divisible by 11
if subtract and then add the digits in an alternating pattern from left to right
and number got should be divisible by 11
4 - 0 + x - y + y - 1 + 2 - 9
= x - 4
=> x = 4
x + 2y + 16
= 4 + 2y + 16
= 20 + 2y
y = 2 , 5 , 8
x = 4
y = 2 , 5 , 8
Numbers
40422129
40455129
40488129
Learn more:
1. Check the divisibility of the following numbers by 2, 3, 9 and 11 a ...
https://brainly.in/question/12343368
If a six digit number 93p25q is divisible by 88 then find the value of p ...
https://brainly.in/question/3788301
if a 10 digit number 2094x843y2 divisible by 88 then the value of (5x ...
https://brainly.in/question/11094736