Question

A number 600 +30+ C multiplied by 3 to get a number exactly divisible by 9 find the value of C.
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Answer 1

Answer:

600+30= 630

630

×3=1890

1890÷9=210

Step-by-step explanation:

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Answer 2

Answer:

C = 207

Step-by-step explanation:

Sum of the no. = 600+30+C

= 630+C

No. to be multiplied by 3 = 630+C*3

=1890+3C

No. should be exactly divisible by 9

=1890+3C/9

=210+3C

C = 210-3

C = 207...