Question

A number 600 +30+ C multiplied by 3 to get a number exactly divisible by 9 find the value of C.​

Answer 1

Step-by-step explanation:

3(600 + 30 + C) = x

1800 + 900 + 3C = x

since x is exactly divisible by 9

(2700 + 3C) /9 = x/9

300 + 1/3C = x/9

let x be 3600 simply assuming as it will be exactly divisible

1/3 C = 400-300

C = 100*3

C = 400

there are infinite values of C but u can write anyone