Question

A number 774958N96M to be divisible by 8 and 9, the value of N + M will be

Answer 1

PLEASE MARK AS BRAINLIEST PLEASE BRO PLEASE.....

let p and q be a and b respectively(to simplify question)...then....

for divisible by 8

last 3 digits should be divisible by 8

i.e. 9 6 B

so B= 0 or 8

NOW

for divisible by 9,sum of digits in number shud b divisible by 9

so,  

7+7+4+9+5+8+A+9+6+B=55+A+B

IF B=0,A=8, WHICH GIVES SUM =63 WHICH IS DIVISIBLE BY 96 years agoHelpfull: Yes(6) No(0)if the last 3 digits of the number are divisible by 8, so is the entire number.

i.e B must be 8 or o.

also, If the sum of digits is divisible by 9, so is the number.

thus 55 + A + B must be divisible by 9.

if B is 8 then A is 0 or if B is 0 then A is 8.

thus answer is (8,0).6 years agoHelpfull: Yes(2) No(0)if sum of the digits of the number is divisible by 9, then that number is divisible by 9.

so, 7+7+4+9+5+8+A+9+6+B=55+A+B is divisible by 9------>(1),

if the number formed by the last three digits of the number is divisible by 8, then that number is divisible by 8.

so, 96B is divisible by 9---->(2),

by using options which is satisfying the equations (1) & (2), we can get the A and B values.

Therefore, option (b) is satisfying the equations (1) & (2).

6 years agoHelpfull: Yes(2) No(0)ans is b)8,06 years agoHelpfull: Yes(1) No(0)8,0 is the answer  

check the divisibilty cond by cross checking wid the options if the last 3 digits of the number are divisible by 8, so is the entire number.

i.e B must be 8 or o.

also, If the sum of digits is divisible by 9, so is the number.

thus 55 + A + B must be divisible by 9.

if B is 8 then A is 0 or if B is 0 then A is 8.

thus answer is (8,0).