Question

A number added to 1/2+1/4+1/8+1/16+1/32 gives 1. what is the number? ​

Answer 1

Answer:

let the no. be x

x+1/2+1/4+1/8+1/16+1/32= 1

lcm of 2,4,8,16,32 is 32.

therefore 1×16/2×16+1×8/4×8+1×4/8×4+1×2/16×2+1/32

=16+8+4+2+1

32

=31

32+x=1

x=1- 31

32

x=1×32-31

32

32-31

32

= 1

32 answer

hope this helps you

thank u

Answer 2

➤ Answer :-

$\tt \longrightarrow( \sf x) + \tt \dfrac{1}{2} + \dfrac{1}{4} + \dfrac{1}{8} + \dfrac{1}{16} + \dfrac{1}{32} = 1$

To find the value of 'x' in the following sum we should subtract sum of all fractions with 1.

Convert the fractions into like fractions by taking the LCM of the denominators i.e, 2,4,8,16 and 32.

LCM of 2,4,8,16 and 32 is 32.

$\tt \longrightarrow 1 - \dfrac{1 \times 16}{2 \times 16} + \dfrac{1 \times 8}{4 \times 8} + \dfrac{1 \times 4}{8 \times 4} + \dfrac{1 \times 2}{16 \times 2} + \dfrac{1}{32}$

$\tt \longrightarrow1 - \dfrac{16}{32} + \dfrac{8}{32} + \dfrac{4}{32} + \dfrac{2}{32} + \dfrac{1}{32}$

$\tt \longrightarrow \dfrac{1}{1} - \dfrac{31}{32}$

Convert them into like fractions by taking the LCM of the denominators i.e, 1 and 32.

LCM of 1 and 32 is 32.

$\tt \longrightarrow \dfrac{1 \times 32}{1 \times 32} - \dfrac{31}{32}$

$\tt \longrightarrow \dfrac{32}{32} - \dfrac{31}{32} = \dfrac{32 - 31}{32}$

$\tt \longrightarrow \dfrac{1}{32}$

$\Huge\therefore$The other number is $\tt\dfrac{1}{32}$

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$\dashrightarrow$Remember……

• While adding or subtracting the fractions, if the fractions are unlike fractions then we should convert them into like fractions by taking the LCM of the denominators.
• While adding or subtracting the fractions, if the fractions are mixed fractions then we should convert them to improper fractions, but the final answer should be written in mixed fractions.