Question

A number and its reciprocal have a sum of 34/15. Find the smaller of these two numbers.​

Answer 1

Answer:

Step-by-step explanation:

x + (1/x) = 34/15

x² + 1 = 34x/15

15x² + 15 = 34x

15x² = 34x - 15

Let's solve your equation step-by-step.

Step 1: Subtract 34x-15 from both sides.

Step 2: Factor left side of equation.

Will be,

(5x-3)(3x-5) = 0

So, it is either 5/3 or 3/5

the smaller one is 3/5