Question

A number being successively divided by 3,5,8 leaves remainders 1,4,7 respectively find the respective remainders if the order of divisors be reversed???

Answer 1

2,1,1.
I don't understand but trying

Answer 2

let x be the dividend here
x = y *3 + 1
y = z * 5 + 4
z = a * 8 + 7

so x = 120* a + 118
now let's divide this with the reverse order i.e 8,5,3

first with 8 => (120 * a + 118) / 8 since 120 is divisible by 8 we don't need to consider it.
so 118 / 8 which gives us a reminder of 3.

now the number after divided with 8 is 15*a +  14 ......(120*a /8  + 118/8)

now with 5 => you can see the remainder here would be 4 ( because of 16)
and the number became 3*a + 2

which when divided by 3 gives you a remainder of 2

so the final answer is 3,4,2