Question

A number being successively
divided by 5, 7 and 11 leaves 3, 1
and 2 as remainders respectively.
What are the remainder, if the
order of divisors by reversed ? 4​

Answer 1

Step-by-step explanation:

we can find the number by reverse process as.

reminder 2 and Divisor 11 no. is 2+11 = 13(13 divided by 11 reminder will be 2)

now number which divide by 7 and leaves reminder 1 with Quotient 13 is

(13*7)+1 = 92

same (92*5)+3 = 469.

now 469/11 = 42 reminder 7

42/7 = 6 reminder 0

6/5 = 1 remainder 1