a number conisits of two digits, the sum of whose digit is 4 times the original number is equal to 7 times the number obtained by reversing the digits. find the original number
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Let the digits be X and y
the no =10x +y
acc to ques
x+y= 4
x=4 - y
10x + y = 7 ( 10y+ x)
10x+y = 70y + 7x
10x- 7x +y - 70y = 0
3x- 69y=0
x-23y =0
4-y-23y=0
4-24y=0
4=24y
y =1/6
the no =10x +y
acc to ques
x+y= 4
x=4 - y
10x + y = 7 ( 10y+ x)
10x+y = 70y + 7x
10x- 7x +y - 70y = 0
3x- 69y=0
x-23y =0
4-y-23y=0
4-24y=0
4=24y
y =1/6
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