Question

A number consist of 2 digits. The sum of the digits is 12 and the unit digit, when divided by the tens digit gives the result as 3. find the number?​

Answer 1

Answer:

39

Step-by-step explanation:

Let units place = y

Let tens place = x

Number = 10x+y

Given that A no consist of two digits the sum of digits is 12

So, x+y=12  

The unit digit when divided by the ten digit gives the result as 3  

So,  

y=3x  

x+y=12  

x+3x=12  

4x=12  

x=3

y=3x=3(3)=9  

Number = 10x+y=10(3)+9=39  

∴ The number is 39

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Answer 2

let the no. be a and b., a< b

now, the no. is 10a + b

given,

a+b = 12

a = 3b

therefore,

3b + b = 12

4b = 12

b = 3.

a= 9

the no. is 10× 3 + 9

39