a number consist of a two digit no whose sum is 8 if 18 is added to the number the digits are reversed find the number
Answers
Answered by
5
let one digit be x
then x(10)+8-x(1) - 8-x(10)+x(1)=18
10x+8-x-80-10x+x=18
...........
x=3
other 5
no. 35
then x(10)+8-x(1) - 8-x(10)+x(1)=18
10x+8-x-80-10x+x=18
...........
x=3
other 5
no. 35
Answered by
2
Answer:
Let the one number be x and another number be 8 - x.
10x + (8 - x) + 28 = 10(8 - x) + x
10x + 8 - x + 18 = 80 - 10x + x
9x + 26 = 80 - 9x
9x + 9x = 80 - 26
18x = 54
x = 3
Therefore,
One number = x = 2
Other number = (8 - x) = 8 - 3 = 5
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