a number consist of of two digits whose sum is 8. if 18 is added to the number its digit are reversed. find the number.
Answers
Answered by
22
let digit at tens place be x and units place be y
hence no is 10x+y
now x+y=8........1
and
10x+y+18=10y+x
9y-9x=18
y-x=2..........2
by 1 and 2
2y=10
y=5
x=3
no is 35
hence no is 10x+y
now x+y=8........1
and
10x+y+18=10y+x
9y-9x=18
y-x=2..........2
by 1 and 2
2y=10
y=5
x=3
no is 35
Answered by
9
X+y = 8
10x + y +18 = 10y + X
10x-x+y-10y = 18
9x-9y = 18
9(x-y) = 18
x-y = 2
X = y-8
8-y-y= 2
-2y = -6
2y=6
y= 3
X+y = 8
x= 8-3
= 5
therefore the numbers are 35 and 53
35+18= 53
hence proved
10x + y +18 = 10y + X
10x-x+y-10y = 18
9x-9y = 18
9(x-y) = 18
x-y = 2
X = y-8
8-y-y= 2
-2y = -6
2y=6
y= 3
X+y = 8
x= 8-3
= 5
therefore the numbers are 35 and 53
35+18= 53
hence proved
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