Math, asked by kanishka115, 1 year ago

a number consist of of two digits whose sum is 8. if 18 is added to the number its digit are reversed. find the number.

Answers

Answered by Anonymous
22
let digit at tens place be x and units place be y
hence no is 10x+y
now x+y=8........1
and
10x+y+18=10y+x
9y-9x=18
y-x=2..........2
by 1 and 2
2y=10
y=5
x=3
no is 35
Answered by saeshwaran2099pdpr5g
9
X+y = 8
10x + y +18 = 10y + X
10x-x+y-10y = 18
9x-9y = 18
9(x-y) = 18
x-y = 2

X = y-8
8-y-y= 2
-2y = -6
2y=6
y= 3
X+y = 8
x= 8-3
= 5
therefore the numbers are 35 and 53
35+18= 53
hence proved

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