a number consist of two digit who's sum is 16. if 18 subtracted from the number. it is digit are reverse. find the number.
Answers
Answer:
97 is the required number
Answer:
Let ten's digit(first no) be x
So ,
Since the sum of two digits is 6
Therefore the second digit(one's digit)= (6-x)
Now, original no=10x+(6-x)
According to the question,
[10x+(6-x)]-18=[10(6-x)+x]
[10x+6-x]-18=[60-10x+x]
9x+6-18=60-9x
9x+9x=60+12
18x=72
x=4
Hence the number is 10x+(6-x)=10(4)+(6–4) i.e.40+2=42
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Kaiser Tarafdar, Physician at Covenant Medical Group
Updated 1 year ago · Author has 2.1K answers and 2.5M answer views
It is -24. Here’s how : the sum of the two digits here is 6 (2 + 4). If you subtract 18 from -24 you get -42 ( -24-18), so now you have the two digits of -24 reversed to -42. The number could also be 42, as if you subtract 18 from it you will get 24, where the digits are interchanged also. So there are two solutions here using negative and positive numbers. KT
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Nick Carlin
Answered 1 year ago
42
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Louis M. Rappeport, B.S. from University of California, Berkeley
Answered 1 year ago · Author has 6.3K answers and 2.4M answer views
Let m and n be the two digits. Then:
m+n=6 and
10m+n-18=10n+m
Solve for m and n …………
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Argyris Sofroniou
Answered 1 year ago · Author has 551 answers and 393.9K answer views
a+b=6 => a=6-b => a=4
10a+b-18=10b+a => 60-10b+b-18=10b+6-b
=> 18b=36 => b=2
n=10a+b=42
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Max Lassley, Self employed (1963-present)
Answered 1 year ago · Author has 1.2K answers and 485.1K answer views
The number is 42. 42–18=24
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