A number consist of two digit whose sum is 7.if 27 is added to the number the digits are reversed .find the no
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Let the unit digit of number be x
and ten's digit be y
So number is 10y+x
It is given that
x+y=7
x = 7-y .....(1)
Revered number will be 10x+y
It is given that if we add 27 to the original number the number gets reversed so..
10y + x + 27 = 10x + y
9y+27=9x
9y+27=9(7-y) ( from (1))
9y+27=63-9y
18y=36
y=2
x=7-2
x=5
The number is 10(2)+5
= 25
and ten's digit be y
So number is 10y+x
It is given that
x+y=7
x = 7-y .....(1)
Revered number will be 10x+y
It is given that if we add 27 to the original number the number gets reversed so..
10y + x + 27 = 10x + y
9y+27=9x
9y+27=9(7-y) ( from (1))
9y+27=63-9y
18y=36
y=2
x=7-2
x=5
The number is 10(2)+5
= 25
jassi1248:
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