Math, asked by IshikaKOCHHAR, 1 year ago

A NUMBER CONSIST OF TWO DIGIT WHOSE SUM IS 8. IF 18 IS ADDED TO THE NUMBER ITS DIGIT ARE REVERSED.FIND THE NUMBERS.











IshikaKOCHHAR: please anyone send the answer fast

Answers

Answered by rahul9835
1005
Hello Friend !

Let us assume that one of the digit of the two digit number is X, then problem the other number will be (8 - X)

From problem we get that, if we add 27 to the number the digits get interchanged and also since the number is a two digit number then X will in tens place (7 - X) will be in ones place.

So the equation we get

10X + (8 - X) + 18 = 10(8 - X) + X

10X + 8 - X + 18 = 80 -10X + X

9X + 26 = 80 - 9X

9X + 9X = 80 - 26

18X = 54

X = 54/18

X = 3,

So the digit in tens place = 3 the digit in ones place is (8 - 3 = 5) , then the number is 35 and when 18 is added the result is 53, the digits interchange their position in the new number.

Ans: 35.


Hope this helps !!

rahul9835: Hope this will helps you !!
rahul9835: ( :
Answered by VishalSharma01
773

Answer:

Step-by-step explanation:

Given :-

Sum of 2-digit number = 8

If 18 is added to the number, the digits change their places.

To Find :-

The Number

Solution :-

Let one of the number be x

And the other number be 8 - x

According to the question

10x + (8 - x) + 18 = 10(8 - x) + x

⇒ 10x + 8 - x + 18 = 80 -10x + x

⇒ 9x + 26 = 80 - 9x

⇒ 9x + 9x = 80 - 26

⇒ 18x = 54

⇒ x = 54/18

x = 3

One Number = x = 3

Other number = 8 - x = 8 - 3 = 5

Hence, the number is 35.

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