A number consist of two digit whose sum is 9.If 27 is sub from the no. Its digit are reversed.Find the no.
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Answer:
let no. be 10x+y
x+y=9.....1
10x+y-27= 10y+x
9x-9y=27
x-y=3......2
from both eqn
x=6
y=3
no is 10x+y=10×6+3=63
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