Question

A number consist of two ✌ digits whose sum is 5. When the digits are reversed the number become greater by 9 find that number

Answer 1

hey mate

this is solution of questions linear equations

Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Question}}}}$

Assume

Number be p

Also,

Ones digit be t

So,

Number = 10p + t

Now,

Reversed Number = 10t + p

Situation,

p + t = 5 ................. (1)

(10p + t) + 9 = (10t + p)

10p + t + 9 = 10t + p = 0

9p - 9t = -9

p - t = - 1 ............... (2)

Now,

From (1) and (2) we have,

2p = 4

p = 4/2

p = 2

Now,

Substitute value of p in (1),

p + t = 5

2 + t = 5

t = 5 - 2

t = 3

Number :-

= 10p + t

= 10(2) + 3

= 23

Therefore

Number = 23