a number consist of two digits whose sum is 6 if 18 is added to the number,its digits are reversed find the number
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Hey!
let the digit in the unit place be X
the digit in the tens place = 6- X
original number = 10(6-x) + x = 60 - 10x + X
=> 60 - 9x
On reversing the digits ---
New number = 10 x + 6-x
=> 9x + 6
original number + 18 = new number
60 - 9x + 18 = 9x +6
78 - 9x = 9x + 6
9x + 9x = 78 - 6
18x = 72
X = 72/18
x= 4
Original number= 24
Hope it will be helpful ✌️
@Mahi
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