Question

a number consist of two digits whose sum is 8. if 18 is added to the number the digits are reversed. find the number.

Answer 1

x+y=8 y=8-x
10x+y+18=10y+X
27x-9y=0
27x-9 (8-x)=0
27x-72+9x=0
36x=72
x=2
y=8-2
y=6
Hope this may help u....

Answer 2

HEY!!

HERE IS YOUR ANSWER..!!

digit at unit place = x
digit at tens place = Y

original no. = 10y + x

It is given that " sum of two digit is 8 ".

x + Y = 8. ..........(1)

Add 18 to the original no. we get reversed digit no.

10y + x + 18 = 10x + Y

9y - 9x + 18 = 0

-9(x - Y - 2) = 0

x - Y = 2. ............(2)

Add eq.(1) and eq.(2)

we get,,

x+Y = 8
x - Y = 2
-----------------
2x = 10
x = 5

Put x value in eq.(1)

X + Y = 8
5 + Y = 8
Y = 3

original no. = 10y + x

= 10(3) + 5
= 30 + 5
= 35

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HOPE IT HELPS....

THANKS......