Question

A number consist of two digits whose sum is 8. If 18 is added to the number its digits are reversed. Find the numbers?​

Answer 1

Let one digit of the number be x , then its ten digits digits will be (8−x) .

So , given number =10(8−x)+x

=80−10x+x

=80−9x

Now if digits are reversed , then Number obtained

=10x+(8−x)

=10x+8−x

=9x+8

According to question

(80−9x)+18=9x+8

98−9x=9x+8

90=18x

x=5

⇒ given number =80−9x

=80−9×5

=80−45

=35